site stats

Hcf of 210 and 55 is in the form 210 5 55 y

WebMar 22, 2024 · 55 = 5 \times 11 \end{array}\] Comparing these two it can be easily seen that there’s only one factor common in these 2 and that is 5. Therefore the HCF of 210 and 55 is 5 only. Therefore for getting the value of y we can generate the equation as \[\begin{array}{l} \therefore 210 \times 5 - 55y = 5\\ \Rightarrow - 55y = 5 - 1050\\ WebFeb 26, 2024 · Let us first find the HCF of 210 and 55. Applying Euclid division lemna on 210 and 55, we get 210 = 55 × 3 + 45 55 = 45 × 1 + 10 45 = 4 × 10 + 5 10 = 5 × 2 + 0 We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55. ∴ 5 = 210 × 5 + 55y ⇒ 55y = 5 - 1050 = -1045 ∴ y = -19 plz mark brainly

HCF of 210 and 55 How to Find HCF of 210, 55?

WebIf the HCF of 210 and 55 is expressible in the form 210 × 5 + 55y, find y. Class 10 >> Maths >> Real Numbers >> Euclid's Division Lemma >> If the HCF of 210 and 55 is expressible Question 4M RKS 12. If the HCF of 210 and 55 is expressible nethe form 210x 5 + 55y then find Solution Verified by Toppr Solve any question of Real Numbers … WebClick here👆to get an answer to your question ️ If HCF of 210 and 55 is of the form (210) (5) + 55 y , then the value of y is : Solve Study Textbooks. Join / Login >> Class 10 >> … how to draw skeletal formula https://new-lavie.com

If the HCF of 210 and 55 is expressible in the form 210 × …

WebIf the HCF of 210 and 55 is expressible in the form 210×5+55y then find …. Ask questions, doubts, problems and we will help you. ... 55=45×1+10.....(2) 45=10×4+5.....(3) 10=5×2+0 So here HCF (210,55)=5 From equation (3), 5 can be written as 5=45—10×4.....(4) Now from (2) 10=55—45×1,now this value substitute in equation (4) in place ... WebIf the HCF of 210 and 55 is expressible in the form to 210×5 + 55 y then find y Login Study Materials NCERT Solutions NCERT Solutions For Class 12 NCERT Solutions For Class 12 Physics NCERT Solutions For Class 12 Chemistry NCERT Solutions For Class 12 Biology NCERT Solutions For Class 12 Maths NCERT Solutions Class 12 Accountancy WebClick here👆to get an answer to your question ️ If H.C.F. of 210 and 55 is expressed in the form of 210 × 5 + 55y, find the value of y^2 . leawood restaurants on stateline

If the HCF of 210 and 55 is expressible in the form 210*5+55y, find y.

Category:If the H.C.F of 210 and 55 is expressible in the form 210×5 - YouTube

Tags:Hcf of 210 and 55 is in the form 210 5 55 y

Hcf of 210 and 55 is in the form 210 5 55 y

If the HCF of 210 and 55 is expressible in the form 210 × …

WebMar 22, 2024 · Comparing these two it can be easily seen that there’s only one factor common in these 2 and that is 5. Therefore the HCF of 210 and 55 is 5 only. Therefore … WebApr 5, 2024 · If the HCF of 210 and 55 is expressible in the form 210 × 5 + 55y, find y. 2Pi classes. 45.3K subscribers. Subscribe. 260 views 11 months ago Maths Class 10 (Real …

Hcf of 210 and 55 is in the form 210 5 55 y

Did you know?

WebIf hcf of 210 and 55 is expressible in the form 210×5-55x. Find x. Math Army 117K subscribers Subscribe 56 Share Save 2.8K views 2 years ago HCF If hcf of 210 and 55 … WebIf the HCF of 210 and 55 is expressible in the form of 210 ×5 -55y find y Q. If H C F of 210 and 55 is expressible in the form 210 ∗ 5 + 55 ∗ A , then find the value of ( 2 − A ) .

WebIf the HCF of 210 and 55 is expressible in the form 210*5+55y, find y. Answers (1) 210 = 2x3x5x7 55=5x11 HCF (210,55) = 5 ATQ 210x5+55y=5 55y = -1045 y =-1045/55 = -19 Posted by Ravindra Pindel Share View full answer WebMay 19, 2024 · the hcf of 210 and 55 is expressible in the form 210*5-55x,find x - 1186370

WebIf H.C.F. of 210 and 55 is expressed in the form of 210 × 5 + 55y, find the value of y2. Q. If HCF of 210 and 55 is expressible in the form 210∗5+55∗A, then find the value of (2−A). … WebApr 3, 2024 · If the HCF of 210 and 55 is expressible in the form of 210×5×55×A ,then find the value of (2-A) - 38201040

WebJun 15, 2024 · Here is the answer Let us first find the HCF of 210 and 55. Applying Euclid division lemna on 210 and 55, we get 210 = 55 × 3 + 45 55 = 45 × 1 + 10 45 = 4 × 10 + 5 10 = 5 × 2 + 0 We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55. ∴ 5 = 210 × 5 + 55y ⇒ 55y = 5 - 1050 = -1045 ∴ y = -19

WebDec 9, 2024 · Evaluate 22. If the HCF (210, 55) is expressible in the form 210 × 5 − 55 y, then find y. OR 25. A heap Prove that the number 4 n, n being a natural number, can never end with the digit 0.2. Viewed by: 5,914 students. Updated on: Dec 9, 2024. ... If the HCF (210, 55) is expressible in the form 210 ... how to draw skeleton headsWebIf the HCF of 210 and 55 is expressible in the form 210 ∗5+55y, find y − Using Euclid's division algorithm, find the HCF of 100 and 190. Solution Verified by Toppr Solve any question of Real Numbers with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions Express the following number as product of powers of prime factors: 24000 how to draw skeleton hands step by stepWebApr 15, 2024 · The value of y is -19. The two numbers = 210 and 5 . HCF can be expressed as 210 x 5 + 55y . The value of y . First we need to find the HCF of 210 and 5. Prime … leawood retirement homesWebApr 11, 2013 · Successful infection of herpes simplex virus is dependent upon chromatin modulation by the cellular coactivator host cell factor-1 (HCF-1). This review focuses on the multiple chromatin modulation components associated with HCF-1 and the chromatin-related dynamics mediated by this coactivator that lead to the initiation of herpes simplex … leawood rotaryWebJun 6, 2024 · Solution :- HCF of 210 and 55 Using Euclid's division algorithm. 210 = (55*3) + 45 55 = (45*1) + 10 45 = (10*4) + 5 10 = (5*2) + 0 So, the remainder is 0 at the last stage, so HCF of 210 and 55 is 5. ∴ 5 = (210*5) + 55y ⇒ 5 = 1050 + 55y ⇒ - 55y = 1050 - 5 ⇒ - 55y = 1045 ⇒ y = - 1045/55 ⇒ y = - 19 Hence, the value of x is 5 and y is - 19 Answer. leawood rental homesWebMay 21, 2015 · Raghunath Reddy Let us first find the HCF of 210 and 55. Applying Euclid division lemna on 210 and 55, we get 210 = 55 × 3 + 45 55 = 45 × 1 + 10 45 = 4 × 10 + 5 10 = 5 × 2 + 0 We observe that the remainder at this stage is zero. So, the last divisor i.e., 5 is the HCF of 210 and 55. ∴ 5 = 210 × 5 + 55y ⇒ 55y = 5 - 1050 = -1045 ∴ y = -19 leawood roasterieWeb210 = 2x3x5x7. 55=5x11. HCF(210,55) = 5. ATQ. 210x5+55y=5. 55y = -1045. y =-1045/55 = -19 leawood rotary club