Find the smallest number when increased by 17
WebHence, 4680 is the smallest number which is exactly divisible by both 520 and 468 i.e. we will get a remainder of 0 in each case. But, we need to find the smallest number which when increased by 17 is exactly divided by 520 and 468. So that is found by, 4680 - … WebMar 11, 2024 · Hey Smart Learners So in this video we are going to solve this question👉🏻 Find the smallest number which when increased by 17 is exactly divisible by both ...
Find the smallest number when increased by 17
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WebMar 30, 2024 · We have to find the smallest number which when increased by $17$ is divisible by two numbers. So, the required number is decreased by $17$ from $4680$. Thus, the required number is $4680 - 17 = 4663$. Note: The LCM (lowest common multiples) of the given two numbers can also be calculated by division method which is a … WebDec 14, 2024 · Shortcut Trick. To find the smallest number which will leave the remainder ‘11’ when divided by 516, 24, 30, and 48. L.C.M of 16, 24, 30, and 48 = 240. Smallest number = 240 × 2 + 11. = 491. Hence, “491” is the correct answer. Download Solution PDF.
WebMar 3, 2024 · The given number are 4, 5, 6 and 7. The smallest number which when increased by 8 is exactly divisible by 4, 5, 6 and 7 = LCM of 4, 5, 6 and 7 – 8. ⇒ LCM of 4, 5, 6 and 7 = 2 × 2 × 5 × 3 × 7. ⇒ 420. The smallest number which when increased by 8 is exactly divisible by 4, 5, 6 and 7 obtained by subtracting 8 from the LCM 420 = 420 – 8. WebMar 11, 2024 · Smallest number which when increased by 11 is exactly divisible by 15, 20 and 54 = Smallest number which when increased by 11 is exactly divisible by 15, 20 and 54 = 529. Explanation: Find the LCM of 15, 20 and 54. Resolve 15,20and 54 as product prime: 15 = 3×5. 20= 2×2×5=2²×5. 54 = 2×3×3×3=2×3³. Therefore, LCM(15,20,54) = …
WebApr 23, 2024 · Hi All, This question includes a number of great Number Property shortcuts that you can take advantage of: 1) The question asks for the SMALLEST number that, when increased by 5 is divisible by 8, 11 and 24. Since the answers are numbers, we can TEST THE ANSWERS. 2) Any number that is divisible by 24 is ALSO divisible by 8, so … WebMay 3, 2016 · Small number divisible by both 520 and 468 when it is increased by 17 is 4663. Solution: Given: The given numbers are 520 and 468. ... 03.05.2016 Math Primary School answered • expert verified Find the smallest number which when increased by 17 is exactly divisible by both 520 and 468 See answers can it be negative? Advertisement …
WebFor example, 6 × 5 = 30. In this example, 6 and 5 are the factors of 30. 1, 2, 3, 10, 15, and 30 would also be factors of 30. Essentially, an integer a is a factor of another integer b, so long as b can be divided by a with no remainder. Factors are important when working with fractions, as well as when trying to find patterns within numbers. cyclavance comprarWebApr 12, 2024 · Find the smallest number which when increased by 20 is exactly divisible by 90 and 144. Asked by Kirti 04/12/2024 Last Modified 22/01/2024. 4 Answers. ... Lcm of 90 and 144 is= 720,it is the smallest number that is divisible by 90 and144. So number is = 700 answer which is increased by 20 will be 720. 0. Comments. Dislike Bookmark. ra kuhlmannWebOct 9, 2024 · To Find:-The smallest number which when divided by 17, 23 and 29 leaves a remainder 11 in each case is : (a) 493 (b) 11350 (c) 11339 (d) 667. Concept used:-The least number which when divided by x, y and z leaves the same remainder ‘r’ each case is :- (LCM of x, y and z) + r . Solution:-. from above told concept, → Required number = … ra kolkataWebAug 2, 2024 · What is the smallest number which when increased by 5 is divisible by 12, 18 and 30? ... What approximate value should come in the place of the question mark ‘?’ in the following question? 11.11% of 99.17 + 22.22% of 98.87 - 9.89% of 100.12 = ? ... If each one likes at least one of these two games, then find the ratio between the number of ... cybex travel strollerWebFind the smallest number which when increased by 20 is exactly divisible by 90 and 144.Part 32 of Real No. Class-10th(CBSE)same type question link :-Part 33... ra kimmelWebFind the smallest number which when increased by 17 is exactly divisible by.Real Numbers- 10th maths - YouTube Real Numbers..Important Sums..1. Find the smallest … ra kubattaWebSep 25, 2013 · LCM of 36, 63 and 108 is 756. given that the smallest number when increased by 6 is divisible by the given numbers. Hence the smallest number is (756 –6) = 750. Recommend (3) (0) person. Prisha. take HCF of 36, 63 and 108 = 1134. now subtract 6 from 1134 = 1134 - 6 = 1128. therefor ans = 1128. cycle bell price